有三道化简题,大家帮忙啊1.(x-2y+1)^2-(x+2y-3分之2)(x-2y+3分之2)2.(4+a)(16-4a+a^2)-(2-a)^33.(x-y)[(x+y)^2-xy](x^3+y^3)-(x+y)^3(x-y)^3
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/12 12:38:03
![有三道化简题,大家帮忙啊1.(x-2y+1)^2-(x+2y-3分之2)(x-2y+3分之2)2.(4+a)(16-4a+a^2)-(2-a)^33.(x-y)[(x+y)^2-xy](x^3+y^3)-(x+y)^3(x-y)^3](/uploads/image/z/1801715-59-5.jpg?t=%E6%9C%89%E4%B8%89%E9%81%93%E5%8C%96%E7%AE%80%E9%A2%98%2C%E5%A4%A7%E5%AE%B6%E5%B8%AE%E5%BF%99%E5%95%8A1.%EF%BC%88x%EF%BC%8D2y%EF%BC%8B1%EF%BC%89%5E2%EF%BC%8D%EF%BC%88x%EF%BC%8B2y%EF%BC%8D3%E5%88%86%E4%B9%8B2%EF%BC%89%EF%BC%88x%EF%BC%8D2y%EF%BC%8B3%E5%88%86%E4%B9%8B2%EF%BC%892.%EF%BC%884%EF%BC%8Ba%EF%BC%89%EF%BC%8816%EF%BC%8D4a%EF%BC%8Ba%5E2%EF%BC%89%EF%BC%8D%EF%BC%882%EF%BC%8Da%EF%BC%89%5E33.%EF%BC%88x%EF%BC%8Dy%EF%BC%89%5B%28x%2By%29%5E2%EF%BC%8Dxy%5D%28x%5E3%2By%5E3%29%EF%BC%8D%28x%2By%29%5E3%28x-y%29%5E3)
有三道化简题,大家帮忙啊1.(x-2y+1)^2-(x+2y-3分之2)(x-2y+3分之2)2.(4+a)(16-4a+a^2)-(2-a)^33.(x-y)[(x+y)^2-xy](x^3+y^3)-(x+y)^3(x-y)^3
有三道化简题,大家帮忙啊
1.(x-2y+1)^2-(x+2y-3分之2)(x-2y+3分之2)
2.(4+a)(16-4a+a^2)-(2-a)^3
3.(x-y)[(x+y)^2-xy](x^3+y^3)-(x+y)^3(x-y)^3
有三道化简题,大家帮忙啊1.(x-2y+1)^2-(x+2y-3分之2)(x-2y+3分之2)2.(4+a)(16-4a+a^2)-(2-a)^33.(x-y)[(x+y)^2-xy](x^3+y^3)-(x+y)^3(x-y)^3
1.(x-2y+1)^2-(x+2y-3分之2)(x-2y+3分之2)
=(x-2y+1)^2-[x+(2y-3分之2)][x-(2y-3分之2)]
=(x-2y+1)^2-[x^2-(2y-3分之2)^2]
=x^2-2x(2y-1)+(2y-1)^2-x^2+(2y-3分之2)^2
=(2y-1)^2-2x(2y-1)+(2y-3分之2)^2
=4y^2-4y+1-4xy+2x+4y^2-8y/3+4/9
=8y^2-20y/3-4xy+2x+13/9
2.(4+a)(16-4a+a^2)-(2-a)^3
=(4+a)[12+(2-a)^2]-(2-a)^3
=12(4+a)+(4+a)(2-a)^2-(2-a)^3
=12(4+a)+(4+a-2+a)(2-a)^2
=12(4+a)+2(1+a)(2-a)^2
3.(x-y)[(x+y)^2-xy](x^3+y^3)-(x+y)^3(x-y)^3
=(x-y)(x+y)^2(x^3+y^3)-(x-y)xy(x^3+y^3)-(x+y)^3(x-y)^3
=(x-y)(x+y)^2[(x^3+y^3)-(x+y)(x-y)^2]-(x-y)xy(x^3+y^3)
=(x-y)(x+y)^2[x^3+y^3-(x^2-y^2)(x-y)]-(x-y)xy(x^3+y^3)
=(x-y)(x+y)^2[x^3+y^3-(x^3-x^2y-xy^2+y^3)]-(x-y)xy(x^3+y^3)
=(x-y)(x+y)^2(x^2y+xy^2)-(x-y)xy(x^3+y^3)
=(x-y)xy(x+y)^3-(x-y)xy(x^3+y^3)
=(x-y)xy(x^3+3x^2y+3xy^2+y^3-x^3-y^3)
=(x-y)xy(3x^2y+3xy^2)
=3x^2y^2(x+y)(x-y)