如果有理数a、b满足|ab-2|+(1-b)平方=0求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+2012)(b+2012)请讲详细一点说明为什么,3q
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![如果有理数a、b满足|ab-2|+(1-b)平方=0求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+2012)(b+2012)请讲详细一点说明为什么,3q](/uploads/image/z/1812252-12-2.jpg?t=%E5%A6%82%E6%9E%9C%E6%9C%89%E7%90%86%E6%95%B0a%E3%80%81b%E6%BB%A1%E8%B6%B3%7Cab-2%7C%2B%281-b%29%E5%B9%B3%E6%96%B9%3D0%E6%B1%821%2Fab%2B1%2F%28a%2B1%29%28b%2B1%29%2B1%2F%28a%2B2%29%28b%2B2%29%2B%E2%80%A6%E2%80%A6%2B1%2F%28a%2B2012%29%28b%2B2012%29%E8%AF%B7%E8%AE%B2%E8%AF%A6%E7%BB%86%E4%B8%80%E7%82%B9%E8%AF%B4%E6%98%8E%E4%B8%BA%E4%BB%80%E4%B9%88%2C3q)
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如果有理数a、b满足|ab-2|+(1-b)平方=0求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+2012)(b+2012)请讲详细一点说明为什么,3q
如果有理数a、b满足|ab-2|+(1-b)平方=0
求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+2012)(b+2012)
请讲详细一点说明为什么,3q
如果有理数a、b满足|ab-2|+(1-b)平方=0求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+2012)(b+2012)请讲详细一点说明为什么,3q
根据题意得
ab-2=0
1-b=0
∴a=2
b=1
∴原式=1/1×2+1/2×3+1/3×4+……+1/2013×2014
=1/1-1/2+1/2-1/3+1/3-1/4+……+1/2013-1/2014
=1-1/2014
=2013/2014
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