已知复数z=x+yi满足|z|=1,求复数|z-1-i|的取值范围∵|z|=1∴√(x^2+y^2)=1,x^2+y^2=1|z-1-i|=|x+yi-1-i|=|(x-1)+(y-1)i|- 之后怎么做啊?- 觉得不对了
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![已知复数z=x+yi满足|z|=1,求复数|z-1-i|的取值范围∵|z|=1∴√(x^2+y^2)=1,x^2+y^2=1|z-1-i|=|x+yi-1-i|=|(x-1)+(y-1)i|- 之后怎么做啊?- 觉得不对了](/uploads/image/z/1819499-59-9.jpg?t=%E5%B7%B2%E7%9F%A5%E5%A4%8D%E6%95%B0z%3Dx%2Byi%E6%BB%A1%E8%B6%B3%7Cz%7C%3D1%2C%E6%B1%82%E5%A4%8D%E6%95%B0%7Cz-1-i%7C%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%E2%88%B5%7Cz%7C%3D1%E2%88%B4%E2%88%9A%EF%BC%88x%5E2%2By%5E2%EF%BC%89%3D1%2Cx%5E2%2By%5E2%3D1%7Cz-1-i%7C%3D%7Cx%2Byi-1-i%7C%3D%7C%28x-1%29%2B%28y-1%29i%7C-+%E4%B9%8B%E5%90%8E%E6%80%8E%E4%B9%88%E5%81%9A%E5%95%8A%3F-+%E8%A7%89%E5%BE%97%E4%B8%8D%E5%AF%B9%E4%BA%86)
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