求函数y=(1/2)^(1+2x-x^2)的定义域,值域及单调区间.
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![求函数y=(1/2)^(1+2x-x^2)的定义域,值域及单调区间.](/uploads/image/z/1992696-24-6.jpg?t=%E6%B1%82%E5%87%BD%E6%95%B0y%3D%EF%BC%881%2F2%EF%BC%89%5E%EF%BC%881%2B2x-x%5E2%EF%BC%89%E7%9A%84%E5%AE%9A%E4%B9%89%E5%9F%9F%2C%E5%80%BC%E5%9F%9F%E5%8F%8A%E5%8D%95%E8%B0%83%E5%8C%BA%E9%97%B4.)
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