设函数f(x)=ax²+bx+c(a>0)且f(1)= -a/2..(1)求证:函数f(x)有两个零点(2)设x1.x2是函数设函数f(x)=ax²+bx+c(a>0)且f(1)= -a/2..(1)求证:函数f(x)有两个零点(2)设x1.x
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![设函数f(x)=ax²+bx+c(a>0)且f(1)= -a/2..(1)求证:函数f(x)有两个零点(2)设x1.x2是函数设函数f(x)=ax²+bx+c(a>0)且f(1)= -a/2..(1)求证:函数f(x)有两个零点(2)设x1.x](/uploads/image/z/2083937-41-7.jpg?t=%E8%AE%BE%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3Dax%26sup2%3B%2Bbx%2Bc%EF%BC%88a%EF%BC%9E0%EF%BC%89%E4%B8%94f%EF%BC%881%EF%BC%89%3D+-a%2F2..%EF%BC%881%EF%BC%89%E6%B1%82%E8%AF%81%EF%BC%9A%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%E6%9C%89%E4%B8%A4%E4%B8%AA%E9%9B%B6%E7%82%B9%EF%BC%882%EF%BC%89%E8%AE%BEx1.x2%E6%98%AF%E5%87%BD%E6%95%B0%E8%AE%BE%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3Dax%26sup2%3B%2Bbx%2Bc%EF%BC%88a%EF%BC%9E0%EF%BC%89%E4%B8%94f%EF%BC%881%EF%BC%89%3D+-a%2F2..%EF%BC%881%EF%BC%89%E6%B1%82%E8%AF%81%EF%BC%9A%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%E6%9C%89%E4%B8%A4%E4%B8%AA%E9%9B%B6%E7%82%B9%EF%BC%882%EF%BC%89%E8%AE%BEx1.x)
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