求函数y=sin(π/3+4x)+cos(4x-π/6)的单调区间

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/31 15:48:40
求函数y=sin(π/3+4x)+cos(4x-π/6)的单调区间
x){igS7Tgio76N/04jy;ņ=^NbTO>;mģ,* ThScA區b0pI}X}p ]#@ F3zwQ<;P o

求函数y=sin(π/3+4x)+cos(4x-π/6)的单调区间
求函数y=sin(π/3+4x)+cos(4x-π/6)的单调区间

求函数y=sin(π/3+4x)+cos(4x-π/6)的单调区间
y=sin(π/3+4x)+cos(4x-π/6)
=sin(π/3+4x)+sin(π/2-4x+π/6)
=sin(π/3+4x)+sin(2π/3-4x)
=2sin[(π/3+4x+2π/3-4x)/2]cos[(π/3+4x-2π/3+4x)/2]
=2sin(π/2)cos(4x-π/6)
=2cos(4x-π/6)
当2kπ