1.三角函数合一公式是怎么推导的?如下:(1)a*sin(a)+b*cos(a)=根号(a^2+b^2)sin(a+c) [其中,tan(c)=b/a]为什么tan(c)=b/a?(2)a*sin(a)-b*cos(a)=sqrt(a^2+b^2)cos(a-c) [其中,tan(c)=a/b]为什么tan(c)=a/b?2.合一公式一般怎么用?
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![1.三角函数合一公式是怎么推导的?如下:(1)a*sin(a)+b*cos(a)=根号(a^2+b^2)sin(a+c) [其中,tan(c)=b/a]为什么tan(c)=b/a?(2)a*sin(a)-b*cos(a)=sqrt(a^2+b^2)cos(a-c) [其中,tan(c)=a/b]为什么tan(c)=a/b?2.合一公式一般怎么用?](/uploads/image/z/2186320-40-0.jpg?t=1.%E4%B8%89%E8%A7%92%E5%87%BD%E6%95%B0%E5%90%88%E4%B8%80%E5%85%AC%E5%BC%8F%E6%98%AF%E6%80%8E%E4%B9%88%E6%8E%A8%E5%AF%BC%E7%9A%84%3F%E5%A6%82%E4%B8%8B%EF%BC%9A%281%29a%2Asin%28a%29%2Bb%2Acos%28a%29%3D%E6%A0%B9%E5%8F%B7%28a%5E2%2Bb%5E2%29sin%28a%2Bc%29+%5B%E5%85%B6%E4%B8%AD%2Ctan%28c%29%3Db%2Fa%5D%E4%B8%BA%E4%BB%80%E4%B9%88tan%28c%29%3Db%2Fa%3F%282%29a%2Asin%28a%29-b%2Acos%28a%29%3Dsqrt%28a%5E2%2Bb%5E2%29cos%28a-c%29+%5B%E5%85%B6%E4%B8%AD%2Ctan%28c%29%3Da%2Fb%5D%E4%B8%BA%E4%BB%80%E4%B9%88tan%28c%29%3Da%2Fb%3F2.%E5%90%88%E4%B8%80%E5%85%AC%E5%BC%8F%E4%B8%80%E8%88%AC%E6%80%8E%E4%B9%88%E7%94%A8%3F)
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