kx-12=3x+3k,x为整数,求k.

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kx-12=3x+3k,x为整数,求k.
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kx-12=3x+3k,x为整数,求k.
kx-12=3x+3k,x为整数,求k.

kx-12=3x+3k,x为整数,求k.
(k-3)x=3k+12
x=(3k+12)/(k-3)
=3+21/(k-3)
即21能被(k-3)整除,k-3=1或3或7或21
k=4或6或10或24

由kx-12=3x+3k
(k-3)x=3k+12
x=(3k+12)/(k-3)
=3(k+4)/(k-3)
=[3(k-3)+21]/(k-3)
x为整数,只需满足21/(k-3)为整数即可
所以 k=10 或 k=6