设二维随机变量(X,Y)的概率密度为f(x,y)=1(0
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设二维随机变量(X,Y)的概率密度为f(x,y)=1(0
设二维随机变量(X,Y)的概率密度为f(x,y)=1(0<=x<=1,0<=y<=1,求p{x+y>1}等于多少
设二维随机变量(X,Y)的概率密度为f(x,y)=1(0
从所给联合密度知属于二维均匀分布,概率可用面积之比计算.x+y=1刚好是正方形区域的对角线,故P{X+Y>1}=1/2
没有看到什么 问题。。。。请补充
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