sin^4a-cos^4a=sin^2-cos^2a
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sin^4a-cos^4a=sin^2-cos^2a
sin^4a-cos^4a=sin^2-cos^2a
sin^4a-cos^4a=sin^2-cos^2a
运用平方差公式和恒等式sin²a+cos²a=1
sin⁴a-cos⁴a=(sin²a+cos²a)(sin²a-cos²a)=sin²a-cos²a
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sin^4a-cos^4a
=(sin^2+cos^2a)(sin^2-cos^2a)
=sin^2-cos^2a
sin^4+sin^2cos^2+cos^2a=
(cos a)^4+(sin a)^2*(sin a)^2+(sin a)^2=?
cosA+cos^2A=1,sin^2A+sin^4A+sin^8A
sin^4a-cos^4a=sin^2a-cos^2a
证明sin^4a-cos^4a=sin^2a-cos^2a
tan a =3求4sin a-2cos a/5cos+3sin a
sin^4a-cos^4a=sin^2-cos^2a
=1-(sin^6a+cos^6a) ------(1)=1-(sin^a+cos^a)(sin^4 a-sin^acos6a+cos^4 a) --------(2)由(1)怎么能到(2)呢=1-(sin^6a+cos^6a)=1-(sin^2a+cos^2a)(sin^4 a-sin^2acos^2a+cos^4a)
Sin^4a-cos^4a=
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(1-sin^6a-cos^6a)/(sin^2a-sin^4a)
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