化简cos(5/2π+α)
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/26 21:00:34
![化简cos(5/2π+α)](/uploads/image/z/2469917-29-7.jpg?t=%E5%8C%96%E7%AE%80cos%285%2F2%CF%80%2B%CE%B1%29)
x){3b
S}
6j$c/(~OD,"dRbgi@9Og\4龎f^Vsi{u.ԯ/.H̳ P
化简cos(5/2π+α)
化简cos(5/2π+α)
化简cos(5/2π+α)
cos(5/2π+a)
=cos(2π+1/2π+a)
=cos(1/2π+a)
=-sin(a)
做题很辛苦~\(≧▽≦)/~
[sin(5π-α)cos(-π-α)]/[cos(α-π)cos(π/2+α)]化简
cos^2α+cos^2(α+π/3)-cosαcos(α+π/3)化简
化简cos(5/2π+α)
2sinα*cosα*cos(2π-α)+cos(π+2α)*cosα*tanα化简!
cos(α+5π/12)cos(α+π/6)+cos(π/12-α)cos(π/3-α) 化简
化简:cosα+cos(2π/3-α)+cos(2π/3+α)
化简:cos(-π-α)
化简sin(α-5π)/cos(3π-α)×cos(π/2-α)/sin(α-3π)×cos(8π-α)/sin(-α-4π)
计算:cos(π/5)+cos(2π/5)+cos(3π/5)+cos(4π/5)
【2cos³α-cos²α+cosα-2】/2cos²α+cosα+2化简
求值:cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)
求值:cos(π/11)-cos(2π/11)+cos(3π/11)-cos(4π/11)+cos(5π/11)
cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)
化简sin(π/2+α)cos(3π-α)tan(π+α)/cos(π/2-α)cos(-α-π)
化简{sin(π+α)^3cos(-α)cos(π+α)}/{tan(π+α)^3cos(-π-α)^2}
5cos^2a+4cos^2β=4cosα则cos^2a+cos^2β
(1+sinα+cosα)*[sin(α/2)-cos(α/2)]/√(2+2cosα)化简 (3/2*π
化简[tan(2π-α)sin(-2π-α)cos(6π-α)]/[cos(α-π)sin(5π-α)]