已知a,b为非零向量,m=a+tb,若|a|=1,b=|2|,当且仅当t=0.25时,|m|取得最小值,则向量a,b的夹角为?高考急用~~
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![已知a,b为非零向量,m=a+tb,若|a|=1,b=|2|,当且仅当t=0.25时,|m|取得最小值,则向量a,b的夹角为?高考急用~~](/uploads/image/z/2476838-38-8.jpg?t=%E5%B7%B2%E7%9F%A5a%2Cb%E4%B8%BA%E9%9D%9E%E9%9B%B6%E5%90%91%E9%87%8F%2Cm%3Da%2Btb%2C%E8%8B%A5%7Ca%7C%3D1%2Cb%3D%7C2%7C%2C%E5%BD%93%E4%B8%94%E4%BB%85%E5%BD%93t%3D0.25%E6%97%B6%2C%7Cm%7C%E5%8F%96%E5%BE%97%E6%9C%80%E5%B0%8F%E5%80%BC%2C%E5%88%99%E5%90%91%E9%87%8Fa%2Cb%E7%9A%84%E5%A4%B9%E8%A7%92%E4%B8%BA%3F%E9%AB%98%E8%80%83%E6%80%A5%E7%94%A8%7E%7E)
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