如图,已知△ABC和△AEF中,AB=AC,AE=AF,∠CAB=∠EAF,BE交FC于D点.如图,已知△ABC和△AEF中,AB=AC,AE=AF,∠CAB=∠EAF,BE交FC于D点.(1)当∠CAB=90゜时,求证:BE=CF,BE⊥CF;(2)当∠CAB=60゜时,求∠BOC的度数;(3
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![如图,已知△ABC和△AEF中,AB=AC,AE=AF,∠CAB=∠EAF,BE交FC于D点.如图,已知△ABC和△AEF中,AB=AC,AE=AF,∠CAB=∠EAF,BE交FC于D点.(1)当∠CAB=90゜时,求证:BE=CF,BE⊥CF;(2)当∠CAB=60゜时,求∠BOC的度数;(3](/uploads/image/z/2504811-3-1.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%B7%B2%E7%9F%A5%E2%96%B3ABC%E5%92%8C%E2%96%B3AEF%E4%B8%AD%2CAB%3DAC%2CAE%3DAF%2C%E2%88%A0CAB%3D%E2%88%A0EAF%2CBE%E4%BA%A4FC%E4%BA%8ED%E7%82%B9.%E5%A6%82%E5%9B%BE%2C%E5%B7%B2%E7%9F%A5%E2%96%B3ABC%E5%92%8C%E2%96%B3AEF%E4%B8%AD%2CAB%3DAC%2CAE%3DAF%2C%E2%88%A0CAB%3D%E2%88%A0EAF%2CBE%E4%BA%A4FC%E4%BA%8ED%E7%82%B9%EF%BC%8E%EF%BC%881%EF%BC%89%E5%BD%93%E2%88%A0CAB%3D90%E3%82%9C%E6%97%B6%2C%E6%B1%82%E8%AF%81%EF%BC%9ABE%3DCF%2CBE%E2%8A%A5CF%EF%BC%9B%EF%BC%882%EF%BC%89%E5%BD%93%E2%88%A0CAB%3D60%E3%82%9C%E6%97%B6%2C%E6%B1%82%E2%88%A0BOC%E7%9A%84%E5%BA%A6%E6%95%B0%EF%BC%9B%EF%BC%883)
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