A为三阶矩阵,E为三阶单位矩阵A的三个特征值分别为1,2,-3,则下列矩阵中是可逆矩阵的是:A.A-E B.A+E C.A+3E D.A-2E 为什么答案是B?

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A为三阶矩阵,E为三阶单位矩阵A的三个特征值分别为1,2,-3,则下列矩阵中是可逆矩阵的是:A.A-E B.A+E C.A+3E D.A-2E 为什么答案是B?
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A为三阶矩阵,E为三阶单位矩阵A的三个特征值分别为1,2,-3,则下列矩阵中是可逆矩阵的是:A.A-E B.A+E C.A+3E D.A-2E 为什么答案是B?
A为三阶矩阵,E为三阶单位矩阵A的三个特征值分别为1,2,-3,则下列矩阵中是可逆矩阵的是:A.A-E B.A+E C.A+3E D.A-2E 为什么答案是B?

A为三阶矩阵,E为三阶单位矩阵A的三个特征值分别为1,2,-3,则下列矩阵中是可逆矩阵的是:A.A-E B.A+E C.A+3E D.A-2E 为什么答案是B?
若要A+aE可逆,只需|A+aE|≠0,即a不是-A的特征值,亦即-a不是A的特征值.因此a≠-1,-2,3即可.观察选项,只有A+E可逆,选B.

原因很简单,由Jordan标准化知,A可看作上三角阵,对角线值为1,2,-3.detA=-6.
所以det(A-E)=det(A+3E)=det(A-2E)=0,而det(A+E)=-12<0. 故只有A+E可逆.

|A|的值为三个特征值的乘积,当|A|不为0,则矩阵的秩为3,可逆
|A-E|=(1-1)(2-1)(-3-1)=0
|A+E|=(1+1)(2+1)(-3+1)不为0,选B

Maria Sharapova
Wimbledon women's singles final will be held this Saturday night passion Beijing staged against both were Russian beauty Maria Sharapova and also the Czech genius Colavito baby. To...

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Maria Sharapova
Wimbledon women's singles final will be held this Saturday night passion Beijing staged against both were Russian beauty Maria Sharapova and also the Czech genius Colavito baby. Today, each side have accepted an interview prior to the final, Sharapova admits that she is extremely eager to rediscover the winning feeling the peak period, and never to become outdone Colavito baby also explain their advantages.
Sharapova won his career so far has 3 Grand Slam title, this Wimbledon she seemed to be the first six games to keep a losing, these are her for Sunday's final filled with confidence, Talking about do to prepare yourself for that final, the Russian beauty is extremely relaxed: "Peace Day isn't any various, with no special role to play, I believe I'll sleep a great nap, this is exactly what I need to do to prepare Obviously I wish to win the sport,pink ghd, I'd have said this championship special meaning for me is,buy pink ghd hair straighteners, I wish to rediscover the winning feeling. "Sharapova stated not too long ago compared to their to become more aged, that is easy to face her final essential reason: "I have a big old, more aged psychological aspects of my career recently it's experienced numerous ups and downs, I know how to much more great to face all this, I don't like is individuals who make their own leisurely down, truly, I am very eager to return in the past that winning perspective of field continuously. "
Colavito WTA baby is no doubt the hottest star on the track, get to the last 4 at Wimbledon last year,InStyler Hair Crimping Iron, she went further in his career this year's initial Grand Slam final track, although the final opponent is has three Grand Slam titles and struggle with their own take advantage of Sharapova, but still feel very confident Colavito baby, On this final Sunday when she was bold to point out their benefits where: "Obviously I serve is a big advantage, I love to serve immediately after the attack, and that i love watching men's tennis match,Hair Straightener, Del Potro has been my favorite player, we play much like the , hit the ball very quickly and incredibly flat. "
Colavito also stated he's presently small baby don't really feel nervous, she will 't be in the race for the ear-piercing screams Sharapova feel any be concerned: "I didn't feel any tension, on the contrary I am getting excited about this final I now sleep well and I such as the grass court battle, it can maximize my technical characteristics, so I made a great record. In addition, I don't worry about stadium noise issues, after i entered the race I'd not think about other activities, but simply to focus on their game. semifinal game and that i Azarenka she'll scream, however i don't care,good hair straighteners, I really don't even think it'll bring a lot impact. "

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A为三阶矩阵,E为三阶单位矩阵A的三个特征值分别为1,2,-3,则下列矩阵中是可逆矩阵的是:A.A-E B.A+E C.A+3E D.A-2E 为什么答案是B? 线性代数题 A为三阶矩阵 E为单位矩阵 A^2-E=(A-E)(A+E)=(A+E)(A-E)吗? 设三阶方阵A满足(A+E)3=0,求矩阵A的全部特征值,其中E为三阶单位矩阵. 化简矩阵方程B=((A-3E)*)*B为所求矩阵,A为已知矩阵,E为单位矩阵.A为已知3阶矩阵. A为三阶矩阵,满足E+A,2E+A,e-2a 不可逆,求A的特征值 设A为三阶矩阵,为A的伴随矩阵,且,求. 行列式、矩阵问题第一题如图第二题中,E为三阶单位矩阵,求矩阵X A为三阶对称矩阵,秩为2,A满足A的平方等于A,求|A-E| A为三阶对称矩阵,秩为2,A满足A的平方等于2A,求|A-E| 设A为三阶矩阵,|A|=2,其伴随矩阵为A* …… 求伴随矩阵的伴随矩阵(A*)*, 已知三阶矩阵 的三个特征值为1,-1,2,则A^2+2A+3E 的特征值为 . 线代矩阵设A为三阶矩阵,A的特征值为-2,-1/2,2,则下列矩阵中可逆的是()A E+2AB 3E+2AC 2E+AD A-2E 设A为n 阶矩阵,E 为 n阶单位矩阵,则 A 为三阶矩阵,|A|=2,求|A*| 设 X为三维单位向量,E 为三阶单位矩阵,则矩阵 E-xx的转置 的秩为___. 为啥xx的转置的特征值为0 0(13)设 X为三维单位向量,E 为三阶单位矩阵,则矩阵 Txx E − 的秩为________. 【答案】 :2 【 设方阵 A=E-2aaT,其中 E 为 n 阶单位矩阵,a 为 n 维单位列向量,证明:A为对称的正交矩阵. 设方阵 A=E-2aaT,其中 E 为 n 阶单位矩阵,a 为 n 维单位列向量,证明:A为对称的正交矩阵. 设A,B,为三队矩阵,其余在哪位朋友帮下忙,E 是单位矩阵,如何与 |A| 相等的呢?我好笨啊