设数列{an}满足a1+3a2+3^2a3+······+3^(n-1)an=n/3,a∈N*.求数列{an}的通项a1+3a2+3^2a3+······+3^(n-2)a(n-1)=(n-1)/3这条式子怎么来的,还有为什么要与题目那条式子相减?
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/18 04:23:24
![设数列{an}满足a1+3a2+3^2a3+······+3^(n-1)an=n/3,a∈N*.求数列{an}的通项a1+3a2+3^2a3+······+3^(n-2)a(n-1)=(n-1)/3这条式子怎么来的,还有为什么要与题目那条式子相减?](/uploads/image/z/2680381-37-1.jpg?t=%E8%AE%BE%E6%95%B0%E5%88%97%EF%BD%9Ban%7D%E6%BB%A1%E8%B6%B3a1%2B3a2%2B3%5E2a3%2B%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%2B3%5E%28n-1%29an%3Dn%2F3%2Ca%E2%88%88N%2A.%E6%B1%82%E6%95%B0%E5%88%97%7Ban%7D%E7%9A%84%E9%80%9A%E9%A1%B9a1%2B3a2%2B3%5E2a3%2B%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%2B3%5E%28n-2%29a%28n-1%29%3D%28n-1%29%2F3%E8%BF%99%E6%9D%A1%E5%BC%8F%E5%AD%90%E6%80%8E%E4%B9%88%E6%9D%A5%E7%9A%84%2C%E8%BF%98%E6%9C%89%E4%B8%BA%E4%BB%80%E4%B9%88%E8%A6%81%E4%B8%8E%E9%A2%98%E7%9B%AE%E9%82%A3%E6%9D%A1%E5%BC%8F%E5%AD%90%E7%9B%B8%E5%87%8F%3F)
xR]n@8XدAPi{jJnIl*@-PB*1RR'Y/q6UږoF9kl.fA/NP!=SVzy+Jyױin<)xvb'o@
收录互联网各类作业题目,免费共享学生作业习题
头条考试网手机作业共收录了 千万级 学生作业题目
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/18 04:23:24