n→∞ lim(n+3/n+1)^2n=
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/25 14:56:27
x){6Q<\tO-PCm#}
4H,
06
5&D65F 1d f-9
n→∞ lim(n+3/n+1)^2n=
n→∞ lim(n+3/n+1)^2n=
n→∞ lim(n+3/n+1)^2n=
原式=lim(1+2/(n+1))^2n
=lim(1+1/(n/2))^((n/2)*4)
=e^4
lim (n!+(n-1)!+(n-2)!+(N-3)!+⋯..+2!+1)/n!其中n→∞
求lim n→∞ (1+2/n)^n+3
lim(n→∞)[1-(2n/n+3)]
lim(n→∞)(2n-1/n+3)
用数列极限证明lim(n→∞)(n^-2)/(n^+n+1)=1中证明如下:lim(n→∞)3n+1/5n-4
lim n→∞ n^(3/2)* (n+1)^(1/2)* (1-cos(π/n))=?
n→∞ lim(n+3/n+1)^2n=
lim(n→∞)[1/(3n+1)+1/(3n+2)+~1/(3n+n)]
求极限lim [ 2^(n+1)+3^(n+1)]/2^n+3^n (n→∞)
lim(n→∞)(3n^3-2n+1)/n^3+n^2 快
计算lim(n→∞)(1^n+2^n+3^n)^(1/n)
lim n →∞ (1^n+3^n+2^n)^1/n,求数列极限
求极限lim(x→∞)(1/n+2/n+3/n..+n/n)
ε-N定义证明 lim(n→∞)(3n^2+n)/(2n^2-1)=3/2,
高数题:lim(n→∞)(1+2∧n+3∧n+4∧n)∧ 1/n=?
lim(n→∞) ((2n!/n!*n)^1/n的极限用定积分求是lim(n→∞) 1/n(2n!/n!)^1/n 不好意思
lim(n→∞) 1/(n+1)-2/(n+1)+3/(n+1)-4/(n+1)+...+[(2n-1)/(n+1)]-[(2n)/(n-1)]求极限
n→∞ lim[1+1/(1+2n)+1/(2+2n)+1/(3+2n)+1/(4+2n).+1/(n+2n)]=