2/1*3+2/3*5+2/5*7+……+2/2003*2005
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2/1*3+2/3*5+2/5*7+……+2/2003*2005
2/1*3+2/3*5+2/5*7+……+2/2003*2005
2/1*3+2/3*5+2/5*7+……+2/2003*2005
2/(1*3)+2/(3*5)+2/(5*7)+……+2/(2003*2005)
=(1/1-1/3)+(1/3-1/5)+(1/5-1/7)+...+(1/2003-1/2005)
=(根据加法的结合率,去掉括号)
=1/1-1/2005
=2004/2005
=2*(3/1+5/3+7/5+.......+2005/2003 =2*[(2003+1)/2+2*(1+1/3+1/5+1/7+........+1/2003)] =2*(1002+2*4.5) =2013 注:那个1+1/3+1/5+1/7+....+1/2003姐不会,就用得程序算出来得,,算出来大概为4.5,, #include<iostream> using namespace std; int main() { int i; float sum=0,n=0; for(i=1;i<=1002;i++){ n=1.0/(2*i-1); sum+=n; } cout<<sum<<endl; return 0; }/*c++*/
裂项相消,先提出个2,再裂
1+3+5+7+9+……+(2n-1)
1+2+3+4+5+6+7+8+……………………………………96+97+98+99+100=
2/1*3+2/3*5+2/5*7+……+2/2003*2005
1+2+3+4+5+6+7……+105
1+2+3+4+5…………+100000000
1/1 -1/3 2/3 -3/3 -2/5 3/5 -4/5 5/5 -1/7 2/7 -3/7 …… 求 98个是多少
1.1/1*2+1/2*3+1/3*4+……+1/99*100 2.2/1*3+2/3*5+2/5*7+……+2/97*99
1+2+3+4+5+6+7+8+9+10+12+13+14+……………………………………………………+9997+9998+9999+10000=?
1+2+3+4+5+6……………………+100000000=?
(1+3+5+7+……+39+41)/(2+4+6+8+……+40+42)
1+2+3+4+5+6+7+8+9+…………+99+100简算
1+2+3+4+5+6+7+8+9…………2000+2001+2002
1+2+3+4+5+6+7+…………997+998+999+1000
1×2×3×4×5×6×7×8×9×10…………×100000
(1+3+5+7……+2013)+(2+4+6+8……+2012)
1+2+3+4+5+6+7…………50+=
1+2+3+4+5+6+7…………+99+100=?5050?
等比数列求和:1/2,3/2^2,5/2^3,7/2^4,……,(2n-1)/2^n,