matlab中怎样确定两曲线交点值大小运行下面程序得两曲线clear;no=2.268;ne=2.2;a=36*pi/180;b=59.5*pi/180;a1=asin(sin(a)./no);b1=asin(sin(b)./no); c1=(a1+b1)./2;c2=(b1-a1)./2;z=2*no.*cos(c1);a2=0.05:0.01:1.57;b2=0.05:0.01:1.57;k1=no.
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/09 03:14:19
![matlab中怎样确定两曲线交点值大小运行下面程序得两曲线clear;no=2.268;ne=2.2;a=36*pi/180;b=59.5*pi/180;a1=asin(sin(a)./no);b1=asin(sin(b)./no); c1=(a1+b1)./2;c2=(b1-a1)./2;z=2*no.*cos(c1);a2=0.05:0.01:1.57;b2=0.05:0.01:1.57;k1=no.](/uploads/image/z/2713737-57-7.jpg?t=matlab%E4%B8%AD%E6%80%8E%E6%A0%B7%E7%A1%AE%E5%AE%9A%E4%B8%A4%E6%9B%B2%E7%BA%BF%E4%BA%A4%E7%82%B9%E5%80%BC%E5%A4%A7%E5%B0%8F%E8%BF%90%E8%A1%8C%E4%B8%8B%E9%9D%A2%E7%A8%8B%E5%BA%8F%E5%BE%97%E4%B8%A4%E6%9B%B2%E7%BA%BFclear%3Bno%3D2.268%3Bne%3D2.2%3Ba%3D36%2Api%2F180%3Bb%3D59.5%2Api%2F180%3Ba1%3Dasin%28sin%28a%29.%2Fno%29%3Bb1%3Dasin%28sin%28b%29.%2Fno%29%3B+c1%3D%28a1%2Bb1%29.%2F2%3Bc2%3D%28b1-a1%29.%2F2%3Bz%3D2%2Ano.%2Acos%28c1%29%3Ba2%3D0.05%3A0.01%3A1.57%3Bb2%3D0.05%3A0.01%3A1.57%3Bk1%3Dno.)
matlab中怎样确定两曲线交点值大小运行下面程序得两曲线clear;no=2.268;ne=2.2;a=36*pi/180;b=59.5*pi/180;a1=asin(sin(a)./no);b1=asin(sin(b)./no); c1=(a1+b1)./2;c2=(b1-a1)./2;z=2*no.*cos(c1);a2=0.05:0.01:1.57;b2=0.05:0.01:1.57;k1=no.
matlab中怎样确定两曲线交点值大小
运行下面程序得两曲线
clear;no=2.268;ne=2.2;a=36*pi/180;b=59.5*pi/180;
a1=asin(sin(a)./no);b1=asin(sin(b)./no);
c1=(a1+b1)./2;c2=(b1-a1)./2;
z=2*no.*cos(c1);
a2=0.05:0.01:1.57;b2=0.05:0.01:1.57;
k1=no.*ne./((no.*cos(a2)).^2+(ne.*sin(a2)).^2).^0.5;
k2=no.*ne./((no.*cos(b2)).^2+(ne.*sin(b2)).^2).^0.5;
k11=(z.^2+k2.^2-2*k2.*z.*cos(b2-c2)).^0.5;
plot(b2,subs(k11),a2,subs(k1))
我想知道当k11=k1时k1,a2和b2的大小,先告诉我如何得出k11,k1两者相同时k1的大小,
matlab中怎样确定两曲线交点值大小运行下面程序得两曲线clear;no=2.268;ne=2.2;a=36*pi/180;b=59.5*pi/180;a1=asin(sin(a)./no);b1=asin(sin(b)./no); c1=(a1+b1)./2;c2=(b1-a1)./2;z=2*no.*cos(c1);a2=0.05:0.01:1.57;b2=0.05:0.01:1.57;k1=no.
用屏幕取坐标函数ginput
clear;no=2.268;ne=2.2;a=36*pi/180;b=59.5*pi/180;
a1=asin(sin(a)./no);b1=asin(sin(b)./no);
c1=(a1+b1)./2;c2=(b1-a1)./2;
z=2*no.*cos(c1);
%a2=0.05:0.01:1.57;
%b2=0.05:0.01:1.57;
a2=0.29:0.01:0.3;
b2=0.29:0.01:0.3;
k1=no.*ne./((no.*cos(a2)).^2+(ne.*sin(a2)).^2).^0.5;
k2=no.*ne./((no.*cos(b2)).^2+(ne.*sin(b2)).^2).^0.5;
k11=(z.^2+k2.^2-2*k2.*z.*cos(b2-c2)).^0.5;
plot(b2,subs(k11),a2,subs(k1))
[a,k]=ginput(1)
图形鼠标将会出现十字,左键点击曲线的交叉点,得到.
a =
0.2912
k =
2.2054