如图,四边形ABCD中,∠C=90°,∠ABD=∠CBD,AB=BC,P是BD上一点,PE⊥BC,PF⊥CD,垂足分别为E,F,求证PA=EF急,
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![如图,四边形ABCD中,∠C=90°,∠ABD=∠CBD,AB=BC,P是BD上一点,PE⊥BC,PF⊥CD,垂足分别为E,F,求证PA=EF急,](/uploads/image/z/2753658-18-8.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9B%9B%E8%BE%B9%E5%BD%A2ABCD%E4%B8%AD%2C%E2%88%A0C%3D90%C2%B0%2C%E2%88%A0ABD%3D%E2%88%A0CBD%2CAB%3DBC%2CP%E6%98%AFBD%E4%B8%8A%E4%B8%80%E7%82%B9%2CPE%E2%8A%A5BC%2CPF%E2%8A%A5CD%2C%E5%9E%82%E8%B6%B3%E5%88%86%E5%88%AB%E4%B8%BAE%2CF%2C%E6%B1%82%E8%AF%81PA%3DEF%E6%80%A5%2C)
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