作业帮∫(1+x)/(X^2)dx=∫ [(1+x)/(X^2)]dx得什么?
来源：学生作业帮助网 编辑：作业帮 时间：2024/07/08 12:06:19
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∫(1+x)/(X^2)dx=∫ [(1+x)/(X^2)]dx得什么?
∫(1+x)/(X^2)dx=
∫ [(1+x)/(X^2)]dx得什么?
∫(1+x)/(X^2)dx=∫ [(1+x)/(X^2)]dx得什么?
答：
∫ [(1+x)/x^2] dx
=∫(1/x^2+1/x)dx
=-1/x+lnx+C
∫ x/(1+X^2)dx=
∫(x+1/x)^2dx=?
∫(1+x)/(X^2)dx=∫ [(1+x)/(X^2)]dx得什么?
∫[dx/(e^x(1+e^2x)]dx
∫1+2x/x(1+x)*dx∫1+2x/x(1+x) * dx
∫(x-1)^2dx,
∫x^1/2dx
∫x[x/[(2a-x)]^(1/2)dx=?
∫dx/x(1+x)
∫1/x^2+x+1dx
∫1/(x^2+x+1)dx
∫dx/x^2(1-x^2)
∫dx/x^2(1+x^2)
∫X^2/1-x^2 dx.
∫X^2/1-x^2 dx.
∫ (x+arctanx)/(1+x^2) dx
∫（x^2+1/x^4)dx
∫2 -1|x²-x|dx