X(1+20%)=100
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/25 05:50:13
xOJ@REȼFlɛ$jD"r!z 4)mUD覻=/m?g s<LY,qLazXa~gnzZ.{`)oO+nob]FL}Uذ* gc ,Ӊ^WJHHqF";t2t$M"9`[*k@qLBh.l7)o[ou G2'B[|K~b
X(1+20%)=100
X(1+20%)=100
X(1+20%)=100
250/3
X等于六分之五百
(20+x)/(100+x)=1/2
(X+X)+(X-X)+(X*X)+(X/X)=100
x*x*(1/4)=20x
x-2=(104-x)+2 6x-59=10x-75 (x+10)+(x-15)=280-x4(x-62)=x-38 60x-40=(60+20)*(x-5) 32x+32*0.5-25x+64x=24x+496-49x x+15=3*(109-x ) 5(3x-1.4)=2(6x-0.5) 3(x+0.9)=5(x-1.7) 13x-4(2x+5)=17(x-2)-4(2x-1) (13x+8)/3=5x-1x-60=2[(3561-x)+100]+1 (x+9)+12=2[(x-9)-1
x/2+x/8+x/12+x/20=1
x/6+x/12+x/20+x/30=1
X+25%X+15%X=420 2X+150=20501.5X-1200=(1+20%)2X-5+X=100
1/X(X+1)+1/(X+1)(X+2)+1/(X+2)(X+3).+1/(X+99)(X+100)=
解方程:2x+4x+6x...+100x=1-(x+3x+5x+...+99x)
1X+2X+3X…+98X+99X+100X=50500X X等于多少?
1x+2x+3x+4x+5x+6x+7x…+99x=100
设函数f(x)=(x-1)(x-2)...(x-100)(x>100),求F'(X)
f(x)=x(x-1)(x-2)…(x-99)(x-100),求f'(100)
解方程X(X+1)-X(X-3)=2(X+1)(X-1)+20
x(x+1)²-x(x²-3)-2(x+1)(x-1)=20
2x(x-1)-x(3x+2)=(-x-1)(x+6)-20
解方程:(1)2x-19=7x+31 (2)20-2x=x-1 (3)19-x=100-10x (4)1/3x+5=2/3x-62x-19=7x+317x-2x=-19-31这里应该是31+19吧?5x=-50x=-50÷5x=-10
解方程:7x-8=5x+2 2x-(5x-3)=3x-4 4(x+1)-2(x-3)=18x-1=4分之1(2x-1) 3x+2(100-x)=300 4x-3(20-x)=6x-7(11-x)