判断分段函数y={x-1(x>0),0(x=0),x+2(x0),0(x=0),x+2(x

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/27 20:25:59
判断分段函数y={x-1(x>0),0(x=0),x+2(x0),0(x=0),x+2(x
x){ڱٴO;ڞ}ﳩ*m]k~OGa dThiT`$S;jOvz:{γ}f{ٌOCys>TqDHF{fAxUؚ

判断分段函数y={x-1(x>0),0(x=0),x+2(x0),0(x=0),x+2(x
判断分段函数y={x-1(x>0),0(x=0),x+2(x0),0(x=0),x+2(x

判断分段函数y={x-1(x>0),0(x=0),x+2(x0),0(x=0),x+2(x
画个图,明显不是奇函数,也不是偶函数.
证明:
设x=5,所以f(5)=5-1=4;
而f(-5)=-5+2=3
所以f(x)≠f(-x)
所以,此分段函数是非奇非偶函数.