若x/3=y=z/4,且xy+xz+yz=76,求2x*x+12y*y+9z*z的值

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若x/3=y=z/4,且xy+xz+yz=76,求2x*x+12y*y+9z*z的值
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若x/3=y=z/4,且xy+xz+yz=76,求2x*x+12y*y+9z*z的值
若x/3=y=z/4,且xy+xz+yz=76,求2x*x+12y*y+9z*z的值

若x/3=y=z/4,且xy+xz+yz=76,求2x*x+12y*y+9z*z的值
xy+xz+yz=76,x/3=y=z/4
所以,19x^2/9=76,x^2=36
2x*x+12y*y+9z*z=58x^2/3=58*12=696