已知集合A={x|-2≤x≤a},B={y|y=2x+3,x∈A},C={z丨z=x2,x∈A},且C包含于B,求a的取值范为什么要以2为标准阿.B:y=2x+3,x∈A所以-2≤x≤a-1≤2x+3≤2a+3即-1≤y≤2a+3C:z=x^2,-2≤x≤a1)当a≥2时,0≤x^2≤a^2,即0≤z≤a^
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![已知集合A={x|-2≤x≤a},B={y|y=2x+3,x∈A},C={z丨z=x2,x∈A},且C包含于B,求a的取值范为什么要以2为标准阿.B:y=2x+3,x∈A所以-2≤x≤a-1≤2x+3≤2a+3即-1≤y≤2a+3C:z=x^2,-2≤x≤a1)当a≥2时,0≤x^2≤a^2,即0≤z≤a^](/uploads/image/z/3000287-47-7.jpg?t=%E5%B7%B2%E7%9F%A5%E9%9B%86%E5%90%88A%3D%7Bx%7C-2%E2%89%A4x%E2%89%A4a%7D%2CB%3D%7By%7Cy%3D2x%2B3%2Cx%E2%88%88A%7D%2CC%3D%7Bz%E4%B8%A8z%3Dx2%2Cx%E2%88%88A%7D%2C%E4%B8%94C%E5%8C%85%E5%90%AB%E4%BA%8EB%2C%E6%B1%82a%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E4%B8%BA%E4%BB%80%E4%B9%88%E8%A6%81%E4%BB%A52%E4%B8%BA%E6%A0%87%E5%87%86%E9%98%BF.B%3Ay%3D2x%2B3%2Cx%E2%88%88A%E6%89%80%E4%BB%A5-2%E2%89%A4x%E2%89%A4a-1%E2%89%A42x%2B3%E2%89%A42a%2B3%E5%8D%B3-1%E2%89%A4y%E2%89%A42a%2B3C%3Az%3Dx%5E2%2C-2%E2%89%A4x%E2%89%A4a1%EF%BC%89%E5%BD%93a%E2%89%A52%E6%97%B6%2C0%E2%89%A4x%5E2%E2%89%A4a%5E2%2C%E5%8D%B30%E2%89%A4z%E2%89%A4a%5E)
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