作业帮6q(p-q)-4p(p+q) x(x-y)²-y(y-x)² x(x+y)(x-y)-x(x+y)²
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6q(p-q)-4p(p+q) x(x-y)²-y(y-x)² x(x+y)(x-y)-x(x+y)²
6q(p-q)-4p(p+q) x(x-y)²-y(y-x)² x(x+y)(x-y)-x(x+y)²
6q(p-q)-4p(p+q) x(x-y)²-y(y-x)² x(x+y)(x-y)-x(x+y)²
6q(p-q)-4p(p+q)
=6pq-6q²-4p²-4pq
=-4p²+2pq-6q²
=-2(2p²-pq+3q²)
.
x(x-y)²-y(y-x)²
=x(x-y)²-y(x-y)²
=(x-y)(x-y)²
=(x-y)³
.
x(x+y)(x-y)-x(x+y)²
=x(x+y)[(x-y)-(x+y)]
=-2xy(x+y)
因式分解 6p+（p+q)-4q(p+q)
6p(p+q)-4q(p+q)如何因式分解?
4p(p-q)-6q(p-q)
6q（p+q）-4p（p+q）
因式分解 6p+（p+q)-4q(p+q)因式分解！！！！！！！！！
分解因式6p(p+q)-4q(p+q),
6q(q+p)-4p(q+p)等于多少?
6p(p+q)-4q(p+q)
分解因式,6p(p+q)-4q(p+q)
6p(p+q)-4q(p+q)
已知集合p={4,5,6}Q={1,2,3} 定义P※Q={x|x=p-q,p∈P,q∈Q}则集合P※Q的所有真子集的个数为?
已知集合P={4,5,6},Q={1,2,3},定义P+Q={X|X=p-q,p属于P,q属于Q},则集合P+Q的所有真子集的个数为?
因式分解：x的平方(p-q)-x(q-p)
6p{(p+q)(p+q)}-4q(p+q)帮我解下
6q(p-q)-4p(p+q) x(x-y)²-y(y-x)² x(x+y)(x-y)-x(x+y)²
不等式(p-q)x其中p≠q.
因式分解：x^2-(p^2+q^2)x+pq(p+q)(p-q)
因式分解：x的平方-(p的平方+q的平方)x+pq(p+q)(p-q)