vb求和,求sin(x)=x/1-x^3/3!+x^5/5!- …… (-1)^(n-1)* x^(2n-1)/(2n-1)!感叹号是阶乘的意思Private Sub Form_Click()Dim x%,,i%,q%x = Val(InputBox("请输入X的值"))Do While t >= 10 ^ (-5)s = s + tn = n + 1For k = 1 To 2 n - 1q = q * kNex

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= 10 ^ (-5)s = s + tn = n + 1For k = 1 To 2 * n - 1q = q * kNex" />

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vb求和,求sin(x)=x/1-x^3/3!+x^5/5!- …… (-1)^(n-1)* x^(2*n-1)/(2n-1)!感叹号是阶乘的意思Private Sub Form_Click()Dim x%,,i%,q%x = Val(InputBox("请输入X的值"))Do While t >= 10 ^ (-5)s = s + tn = n + 1For k = 1 To 2 * n - 1q = q * kNex
vb求和,求sin(x)=x/1-x^3/3!+x^5/5!- …… (-1)^(n-1)* x^(2*n-1)/(2n-1)!感叹号是阶乘的意思
Private Sub Form_Click()
Dim x%,,i%,q%
x = Val(InputBox("请输入X的值"))
Do While t >= 10 ^ (-5)
s = s + t
n = n + 1
For k = 1 To 2 * n - 1
q = q * k
Next k
t = ((-1) ^ (n - 1)) * (x ^ (2 * n - 1)) \ q
Loop
Print "s="; s
End Sub
当第n项的值小于10^-5时结束

vb求和,求sin(x)=x/1-x^3/3!+x^5/5!- …… (-1)^(n-1)* x^(2*n-1)/(2n-1)!感叹号是阶乘的意思Private Sub Form_Click()Dim x%,,i%,q%x = Val(InputBox("请输入X的值"))Do While t >= 10 ^ (-5)s = s + tn = n + 1For k = 1 To 2 * n - 1q = q * kNex
Private Sub Form_Click()
Dim x%,s!,i%,q%
x = Val(InputBox("请输入X的值"))
Do While t >= 10 ^ (-5) '问题出在这里,因为t的初值是0,所以t

VB多项式求和 S=x + x^3/3!+…+x^(2n-1)/(2n-1)! e^x=1+x+x^2/2!+x^3/3!+...+x^n/n!x=9 求和的vb答案是多少 n=25 vb求和,求sin(x)=x/1-x^3/3!+x^5/5!- …… (-1)^(n-1)* x^(2*n-1)/(2n-1)!感叹号是阶乘的意思Private Sub Form_Click()Dim x%,,i%,q%x = Val(InputBox(请输入X的值))Do While t >= 10 ^ (-5)s = s + tn = n + 1For k = 1 To 2 * n - 1q = q * kNex 求极限（（sin(x^3+x^2-x)+sin x) /x x→0 已知lim sinx/x=1 1/cos(x) - tan(x) = 3 求sin(x)1/cos(x) - tan(x) = 3求sin(x) VB利用级数求和法计算,Xn=1+2/x^2+3/x^3+...+n/x^n,x>1,精度要求为10^-5x是自己任意取的吗? 求和x+x^2+x^3+…x^n= 利用求导数求和1^2x+2^2x^2+3^x^3求思路 2sin^2x - 5sin x cos x=3 cos^2x,求X, 已知sin(x)+3cos(x)=2,求sin(x)-cos(x)/sin(x)+cos(x)=? 求不定积分【sin(x)^5 + sin(x)^3】^(1/2) 求方程 sin^3x+cos^5x=1 求和Sn=(x-1)+(x^2-2)+(x^3-3)+…+(x^n-n) 求和:1+x+x^2+.+x^n f'(sin x)=1-cos x 求f''(x) f(x)=sin-1次方 x ,求f'(x) 傅里叶级数作图f（x）=2sin[x] - sin[2x] + 2/3sin[3x] - 1/2sin[4x]我用mathematica输入程序Plot[{2sin[x],-2sin[x],2sin[x] - sin[2x],-2sin[x] + sin[2x],2sin[x] - sin[2x] + 2/3sin[3x],-2sin[x] + sin[2x] - 2/3sin[3x],2sin[x] - sin[2x] + 2/3si 已知sin(x+π/6)=1/3,求sin(5π/6-x)+sin^2(π/3-x)