已知函数f(x)=aln(1+e x次方)-(a+1)x,(其中a>0)点A(x1,f(x1)),B(x2,f(x2)),C(x3,f(x3))从左到右依次是y=f(x)图像上的三点,且2x2=x1+x31,证明:函数f(x)在R上是减函数2,求证:三角形ABC是钝角三角形3,三角形
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![已知函数f(x)=aln(1+e x次方)-(a+1)x,(其中a>0)点A(x1,f(x1)),B(x2,f(x2)),C(x3,f(x3))从左到右依次是y=f(x)图像上的三点,且2x2=x1+x31,证明:函数f(x)在R上是减函数2,求证:三角形ABC是钝角三角形3,三角形](/uploads/image/z/3012367-31-7.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3Daln%281%2Be+x%E6%AC%A1%E6%96%B9%EF%BC%89-%EF%BC%88a%2B1%29x%2C%28%E5%85%B6%E4%B8%ADa%EF%BC%9E0%EF%BC%89%E7%82%B9A%EF%BC%88x1%2Cf%28x1%29%29%2CB%28x2%2Cf%28x2%29%29%2CC%28x3%2Cf%28x3%29%29%E4%BB%8E%E5%B7%A6%E5%88%B0%E5%8F%B3%E4%BE%9D%E6%AC%A1%E6%98%AFy%3Df%28x%29%E5%9B%BE%E5%83%8F%E4%B8%8A%E7%9A%84%E4%B8%89%E7%82%B9%2C%E4%B8%942x2%3Dx1%2Bx31%2C%E8%AF%81%E6%98%8E%EF%BC%9A%E5%87%BD%E6%95%B0f%28x%29%E5%9C%A8R%E4%B8%8A%E6%98%AF%E5%87%8F%E5%87%BD%E6%95%B02%2C%E6%B1%82%E8%AF%81%EF%BC%9A%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E6%98%AF%E9%92%9D%E8%A7%92%E4%B8%89%E8%A7%92%E5%BD%A23%2C%E4%B8%89%E8%A7%92%E5%BD%A2)
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