一道数学几何(比例线段)AD为△ABC的BC边上的中线,CF为任意直线交AD于E 交AB于F求证:AE:ED=2AF:FB可能会用到三角形的重心
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![一道数学几何(比例线段)AD为△ABC的BC边上的中线,CF为任意直线交AD于E 交AB于F求证:AE:ED=2AF:FB可能会用到三角形的重心](/uploads/image/z/3053445-69-5.jpg?t=%E4%B8%80%E9%81%93%E6%95%B0%E5%AD%A6%E5%87%A0%E4%BD%95%EF%BC%88%E6%AF%94%E4%BE%8B%E7%BA%BF%E6%AE%B5%EF%BC%89AD%E4%B8%BA%E2%96%B3ABC%E7%9A%84BC%E8%BE%B9%E4%B8%8A%E7%9A%84%E4%B8%AD%E7%BA%BF%2CCF%E4%B8%BA%E4%BB%BB%E6%84%8F%E7%9B%B4%E7%BA%BF%E4%BA%A4AD%E4%BA%8EE+%E4%BA%A4AB%E4%BA%8EF%E6%B1%82%E8%AF%81%EF%BC%9AAE%EF%BC%9AED%EF%BC%9D2AF%EF%BC%9AFB%E5%8F%AF%E8%83%BD%E4%BC%9A%E7%94%A8%E5%88%B0%E4%B8%89%E8%A7%92%E5%BD%A2%E7%9A%84%E9%87%8D%E5%BF%83)
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