已知tanα=-2求(3sinα-2cosα)/(5sinα+4cosα)求sin^2α+2sinαcosα-3cos^2α
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![已知tanα=-2求(3sinα-2cosα)/(5sinα+4cosα)求sin^2α+2sinαcosα-3cos^2α](/uploads/image/z/3152417-41-7.jpg?t=%E5%B7%B2%E7%9F%A5tan%CE%B1%3D-2%E6%B1%82%283sin%CE%B1-2cos%CE%B1%29%2F%285sin%CE%B1%2B4cos%CE%B1%29%E6%B1%82sin%5E2%CE%B1%2B2sin%CE%B1cos%CE%B1-3cos%5E2%CE%B1)
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