(1)若【存在】a∈[1,3]使不等式ax²+(a-2)x-2>0成立,则x的取值范围是?(2)若【对任意实数】a∈[1,3]使不等式ax²+(a-2)x-2>0成立,则x的取值范围是?(1)若【不存在】a∈[1,3]使不等式ax²+(a-2)x-2
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/05 11:56:39
![(1)若【存在】a∈[1,3]使不等式ax²+(a-2)x-2>0成立,则x的取值范围是?(2)若【对任意实数】a∈[1,3]使不等式ax²+(a-2)x-2>0成立,则x的取值范围是?(1)若【不存在】a∈[1,3]使不等式ax²+(a-2)x-2](/uploads/image/z/3156953-41-3.jpg?t=%281%29%E8%8B%A5%E3%80%90%E5%AD%98%E5%9C%A8%E3%80%91a%E2%88%88%5B1%2C3%5D%E4%BD%BF%E4%B8%8D%E7%AD%89%E5%BC%8Fax%26%23178%3B%2B%28a-2%29x-2%EF%BC%9E0%E6%88%90%E7%AB%8B%2C%E5%88%99x%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%E6%98%AF%3F%282%29%E8%8B%A5%E3%80%90%E5%AF%B9%E4%BB%BB%E6%84%8F%E5%AE%9E%E6%95%B0%E3%80%91a%E2%88%88%5B1%2C3%5D%E4%BD%BF%E4%B8%8D%E7%AD%89%E5%BC%8Fax%26%23178%3B%2B%28a-2%29x-2%EF%BC%9E0%E6%88%90%E7%AB%8B%2C%E5%88%99x%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%E6%98%AF%3F%281%29%E8%8B%A5%E3%80%90%E4%B8%8D%E5%AD%98%E5%9C%A8%E3%80%91a%E2%88%88%5B1%2C3%5D%E4%BD%BF%E4%B8%8D%E7%AD%89%E5%BC%8Fax%26%23178%3B%2B%28a-2%29x-2)
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