一筐橘子,三三数之除余一,五五数之余四,七七数之余二,筐里最少有多少个橘子有算式是用中国剩余定理:1x70+4x21+2x15-105=70+84+30-105=184-105=79
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/21 17:47:03
![一筐橘子,三三数之除余一,五五数之余四,七七数之余二,筐里最少有多少个橘子有算式是用中国剩余定理:1x70+4x21+2x15-105=70+84+30-105=184-105=79](/uploads/image/z/3585297-57-7.jpg?t=%E4%B8%80%E7%AD%90%E6%A9%98%E5%AD%90%2C%E4%B8%89%E4%B8%89%E6%95%B0%E4%B9%8B%E9%99%A4%E4%BD%99%E4%B8%80%2C%E4%BA%94%E4%BA%94%E6%95%B0%E4%B9%8B%E4%BD%99%E5%9B%9B%2C%E4%B8%83%E4%B8%83%E6%95%B0%E4%B9%8B%E4%BD%99%E4%BA%8C%2C%E7%AD%90%E9%87%8C%E6%9C%80%E5%B0%91%E6%9C%89%E5%A4%9A%E5%B0%91%E4%B8%AA%E6%A9%98%E5%AD%90%E6%9C%89%E7%AE%97%E5%BC%8F%E6%98%AF%E7%94%A8%E4%B8%AD%E5%9B%BD%E5%89%A9%E4%BD%99%E5%AE%9A%E7%90%86%EF%BC%9A1x70%2B4x21%2B2x15-105%3D70%2B84%2B30-105%3D184-105%3D79)
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