5x+4y+z=0 3x+y-4z=13 x+y+z=—2
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/30 20:05:31
xPAN@
kshwz Ct]P6JmЪ6&.]Xq?1j$d{{F%AAZx2|8
:.ΰ$)4l&4Wnh% BcJ7$X eV*
P\g|7>@+X8t35=Nbb &M.K#u]1_?%ݫ<K #oV:p`@AXgl_@Ʊb[P͊N܊DXȃ7
m
*;{_̹2"O <<
F/E
5x+4y+z=0 3x+y-4z=13 x+y+z=—2
5x+4y+z=0 3x+y-4z=13 x+y+z=—2
5x+4y+z=0 3x+y-4z=13 x+y+z=—2
①-③,4x+3y=2.④
4*③+②,7x+5y=5.⑤
7*④-4*⑤,y=-6
代入④,x=5
代入③,z=-1
X=5
y=-6
Z=-1
希望我的回答您能满意,如能采纳,不胜荣幸,谢谢!
x=5
y=-6
z=-1
望采纳
X=5 Y=-6 Z=-1
无解
x=5,y=-6,z=-1
正解。。郁闷了。。这样的问题,楼主真不会吗??
5x+4y+z=0 3x+y-4z=13 x+y+z=—2
三元一次方程解 1.{x+y-z=5 {3x+2y+z=2 {2x-2y+z=-31.{x+y-z=5 2.{9x-5y+x=-6 3.{x-y=3 4.{x+y=3 5.{4x-2y+z=7{3x+2y+z=2 {9x+y-2z=3 {x+z=7 {y+z=4 {2x-y-3z=28{2x-2y+z=-3 {-9x+3y-5z=0 {y-z=6 {z+x=5 {x+y-2z=13
六年级三元一次方程组.解下列方程组:(1)5x-3y+z=25x+2y-4z=3-5x+y-z=2(2)x-y-z=-13x_5y+7z=114x-y+2z=-1(3)9x-5y+z=-69x+y+4z=3-9x+3y-5z=0(4)x+y=22x+z=-27y+z=13
已知:4x-5y+2z=0 x+4y-3z=0则:(x*x+y*y+z*z)/(x*y+y*z+z*x)=____.
(x+y):(y+z):(z+x)=3:4:5 3x+y-z=-4已知(x+y):(y+z):(z+x)=3:4:5 ;3x+y-z=-4求x y z
2x+z=10 x+y-z=4 3x-y-z=0
5x+4y+z=-7 4x+y-4z=-13 x+y+z=0
-2X+3Y+Z=-4-X-5Y-2Z=-13X+Y-Z=10
5x+4y+z=0 3x+y-4z=11 x+y+z= -3
已知x+4y-3z=0,4x-5y+2z=0,则x:y:z
已知{x-5y+2z=0 3x-5y-4z=0,求x:y:z
X-Y-Z=0 X+Y-3Z=4 2X-5Y+7Z=21
2x+3y-z=9,x+y+z=15,5x-4y-z=0
已知方程组4x-5y+2z=0 x+2y=3z 则x:y:z
(x+y)/3=(y+z)/5=(z+x)/4 ,xyz不等于0,求x:y:z
若xyz≠0且4(x/z)-5(y/z)=-2,(x/z)+4(y/z)=3,求x:y:z
1.{x:y:z=3:4:5 2x+3y-5z=-142.{x-y-z=-1 3x+5y+7z=11 4x-y+2z=-13.{x+y=1 x+z=0 2x+y+2z=44.{x-y+z=-3 2x-y-z=-2 -3x+y+z=-15.{x-y+z=-3 3x+y-4z=6 2x+y-z=36.{x-2y+5z=16 2x+y-5z=7 2x-y+z=38
数学题在线解答:三元一次方程组;(1)X+Y+Z=0,4X+2Y+Z=0,Z=2;(2)9X+3Y+Z=0,X-Y+Z=0,Z=-3,(3)4X+2Y+Z=5,4X-2Y+Z=1Z=-1;(5)5X+2Y+Z=12,4X+3Y+Z=13,Z=3