如图,已知三角形ABC,以AC和BC为边向外作正三角形ACD和正三角形BCE,BD与AE相交于点M. 求证:AE=BD MC平分角DMC.
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![如图,已知三角形ABC,以AC和BC为边向外作正三角形ACD和正三角形BCE,BD与AE相交于点M. 求证:AE=BD MC平分角DMC.](/uploads/image/z/3718357-61-7.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%B7%B2%E7%9F%A5%E4%B8%89%E8%A7%92%E5%BD%A2ABC%2C%E4%BB%A5AC%E5%92%8CBC%E4%B8%BA%E8%BE%B9%E5%90%91%E5%A4%96%E4%BD%9C%E6%AD%A3%E4%B8%89%E8%A7%92%E5%BD%A2ACD%E5%92%8C%E6%AD%A3%E4%B8%89%E8%A7%92%E5%BD%A2BCE%2CBD%E4%B8%8EAE%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9M.+%E6%B1%82%E8%AF%81%EF%BC%9AAE%3DBD++++++++++++MC%E5%B9%B3%E5%88%86%E8%A7%92DMC.)
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