证明:(1)(3π/2-α)=-cosα (2) (3π/2-α)=-sinα

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/28 18:20:16
证明:(1)(3π/2-α)=-cosα (2) (3π/2-α)=-sinα
x){ٌ{fa~O'2>ߠo{n#g_|nPU@-;&H*PEO'/y7g{kʋKX0@VNRۗطJ|HP&X5X\M dXL!v3H0YgÓK^zKA d `CbY)4p~qAb(5n

证明:(1)(3π/2-α)=-cosα (2) (3π/2-α)=-sinα
证明:(1)(3π/2-α)=-cosα (2) (3π/2-α)=-sinα

证明:(1)(3π/2-α)=-cosα (2) (3π/2-α)=-sinα
哦,原题目应该是:(1)sin(3π/2-α)=-cosα (2) cos(3π/2-α)=-sinα 啊!
证明:(1)左边=sin(2π- π/2 -α)
=sin(-π/2 -α)
=-sin(π/2 +α)
=-cosα
=右边
所以原等式得证.
(2)左边=cos(2π - π/2 - α)
=cos(-π/2 - α)
=cos(π/2 + α)
=-sinα
=右边
所以原等式得证.