△ABC是等边三角形,点D,E是由点B出发的射线上的两点,BD=CE,联结AD,AE,CE,∠1=∠2,证△ADE等边三角形△ABC是等边三角形,点D,E是由点B出发的射线上的两点,满足BD=CE,联结AD,AE,CE,有∠1=∠2,试说明△ADE
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/19 05:38:19
![△ABC是等边三角形,点D,E是由点B出发的射线上的两点,BD=CE,联结AD,AE,CE,∠1=∠2,证△ADE等边三角形△ABC是等边三角形,点D,E是由点B出发的射线上的两点,满足BD=CE,联结AD,AE,CE,有∠1=∠2,试说明△ADE](/uploads/image/z/3788310-30-0.jpg?t=%E2%96%B3ABC%E6%98%AF%E7%AD%89%E8%BE%B9%E4%B8%89%E8%A7%92%E5%BD%A2%2C%E7%82%B9D%2CE%E6%98%AF%E7%94%B1%E7%82%B9B%E5%87%BA%E5%8F%91%E7%9A%84%E5%B0%84%E7%BA%BF%E4%B8%8A%E7%9A%84%E4%B8%A4%E7%82%B9%2CBD%3DCE%2C%E8%81%94%E7%BB%93AD%2CAE%2CCE%2C%E2%88%A01%3D%E2%88%A02%2C%E8%AF%81%E2%96%B3ADE%E7%AD%89%E8%BE%B9%E4%B8%89%E8%A7%92%E5%BD%A2%E2%96%B3ABC%E6%98%AF%E7%AD%89%E8%BE%B9%E4%B8%89%E8%A7%92%E5%BD%A2%2C%E7%82%B9D%2CE%E6%98%AF%E7%94%B1%E7%82%B9B%E5%87%BA%E5%8F%91%E7%9A%84%E5%B0%84%E7%BA%BF%E4%B8%8A%E7%9A%84%E4%B8%A4%E7%82%B9%2C%E6%BB%A1%E8%B6%B3BD%3DCE%2C%E8%81%94%E7%BB%93AD%2CAE%2CCE%2C%E6%9C%89%E2%88%A01%3D%E2%88%A02%2C%E8%AF%95%E8%AF%B4%E6%98%8E%E2%96%B3ADE)
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