m,n满足|m+2|+【√n-9】=0,因式分解【x²+y²】-【mxy+n】
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m,n满足|m+2|+【√n-9】=0,因式分解【x²+y²】-【mxy+n】
m,n满足|m+2|+【√n-9】=0,因式分解【x²+y²】-【mxy+n】
m,n满足|m+2|+【√n-9】=0,因式分解【x²+y²】-【mxy+n】
|m+2|+【√n-9】=0
所以m+2=0,n-9=0
m=-2.n=9
所以原式=x²+y²+2xy-9
=(x-y)²-9
=(x-y+3)(x-y-3)
若m,n满足根号下m+2 +(n-9)的平方=0
那么m+2=0,n-9=0
所以m=-2,n=9
所以(x²+y²)-(-2xy+9)=x²+y²+2xy-9
=(x+y)²-9
=(x+y+3)(x+y-3)
m+2=0;n-9=0
则m=-2 n=9
则
【x²+y²】-【mxy+n】
=x²+y²+2xy-9
=(x+y)^2-3^2
=(x+y+3)(x+y-3)
m,n满足|m+2|+【√n-9】=0,因式分解【x²+y²】-【mxy+n】
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