分式运算(1/a+3)-(6/9-a^)

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/13 01:15:27
分式运算(1/a+3)-(6/9-a^)
x){tOamaoiT_~ f ADm@a%L8QXLS_]$$5@ ~qAb96`TJL_h5.0Mdꂬ6ND+Pnq#bG

分式运算(1/a+3)-(6/9-a^)
分式运算(1/a+3)-(6/9-a^)

分式运算(1/a+3)-(6/9-a^)
(1/a+3)-(6/9-a^2)
=(1/a+3)+(6/a^2-9)
=(a-3+6)/(a^2-9)
=(a-3)/(a-3)(a+3)
=1/(a+3)

1/(a+3)-6/(9-a²)
=1/(a+3)-6/(a+3)(3-a)
=(3-a-6)/(3+a)(3-a)
=-(a+3)/(a+3)(3-a)
=1/(a-3)