等腰三角形ABC中,AB=AC,D是CB延长线上一点,E是BC延长线上一点,且AB^2=DB·CE,如图所示.(1)试说明三角形ADB相似三角形EAC(2)若角BAC=40度,求角DAE的度数
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![等腰三角形ABC中,AB=AC,D是CB延长线上一点,E是BC延长线上一点,且AB^2=DB·CE,如图所示.(1)试说明三角形ADB相似三角形EAC(2)若角BAC=40度,求角DAE的度数](/uploads/image/z/3846735-63-5.jpg?t=%E7%AD%89%E8%85%B0%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2CAB%3DAC%2CD%E6%98%AFCB%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%B8%8A%E4%B8%80%E7%82%B9%2CE%E6%98%AFBC%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%B8%8A%E4%B8%80%E7%82%B9%2C%E4%B8%94AB%5E2%3DDB%C2%B7CE%2C%E5%A6%82%E5%9B%BE%E6%89%80%E7%A4%BA.%EF%BC%881%EF%BC%89%E8%AF%95%E8%AF%B4%E6%98%8E%E4%B8%89%E8%A7%92%E5%BD%A2ADB%E7%9B%B8%E4%BC%BC%E4%B8%89%E8%A7%92%E5%BD%A2EAC%282%29%E8%8B%A5%E8%A7%92BAC%3D40%E5%BA%A6%2C%E6%B1%82%E8%A7%92DAE%E7%9A%84%E5%BA%A6%E6%95%B0)
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