已知[cos(a-b)]^2-[cos(a+b)]^2=1/2,(1+cos2a)(1+cos2b)=1/3求证[tan(a+b)]^2=47还有一条 tan(a/2)=2 求(1+cosa+cos2a+cos3a)/(1-cosa-2(cosa)^2)
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![已知[cos(a-b)]^2-[cos(a+b)]^2=1/2,(1+cos2a)(1+cos2b)=1/3求证[tan(a+b)]^2=47还有一条 tan(a/2)=2 求(1+cosa+cos2a+cos3a)/(1-cosa-2(cosa)^2)](/uploads/image/z/3847484-20-4.jpg?t=%E5%B7%B2%E7%9F%A5%5Bcos%28a-b%29%5D%5E2-%5Bcos%28a%2Bb%29%5D%5E2%3D1%2F2%2C%281%2Bcos2a%29%281%2Bcos2b%29%3D1%2F3%E6%B1%82%E8%AF%81%5Btan%EF%BC%88a%2Bb%29%5D%5E2%3D47%E8%BF%98%E6%9C%89%E4%B8%80%E6%9D%A1+tan%28a%2F2%29%3D2+%E6%B1%82%EF%BC%881%2Bcosa%2Bcos2a%2Bcos3a%29%2F%281-cosa-2%28cosa%29%5E2%29)
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