log2(x-1)
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log2(x-1) log2(x-1)
log2(x-1)
log2 (x-1)
2log2 (x-1)
(x-1)^2<4(2-x),即x^2+2x-7<0,解得:-1-2√2
|[log2(x)]^2-3log2(x)+1|
log2(x+1)>log2(3-x)
log2 (x+1)+log2 x=log6
不等式log2 (x+1)
log2(2X-1)
log2(x²+1)
log2(x-1)
log2(x)=-1
log2(x+1)
log2(x-1)
log2(x-1)
log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1
.log2^(x+1/x+6)
log2(x-1)-log2(x+1)的定义域与值域
不等式|log2^x-1|不等式|(log2^x)-1|
解方程log2(2-x)=log2(x-1)+1
log2(x-1)>2定义域log2(x-1)>2 定义域
解2log2^(x-5)=log2^(x-1)+1