lim(x→0) (5x+sin^2 x -2x^3)/(tanx+4x^2) 用等价无穷小怎么算

lim(x(sin)^2) lim(x→0)×(x-sin²3x)/x 求极限 （（sin(x^3+x^2-x)+sin x) /x x→0 已知lim sinx/x=1 lim sin 2x / sin 5x lim arctan x / xx趋近于0 x趋近于0 lim(x→0)[tan(2x+x^3)/sin(x-x^2)] 1.lim x→0 3x/(sinx-x)2.lim x→0 (1-cosmx)/x^23.lim x→0 sin4x/[(√x+2)-√2]4.lim h →0 [sin(x+h)-sin(x-h)]/h lim (x→0+)sin x/x= lim （x→0）x sin 1/x= lim x→∞ (x+sin 2x)/2 lim(x趋向0) x^2 / (sin^2) * x/3 lim(x趋向0) x^2 / (sin^2) * x/3 lim(x趋向0)ln(1+sin x)/x^2 求极限lim(x-->0)x^2 sin(1/x), 求lim(x~无限大)(sin(x^(2)+5)/x^2) lim→0 sin^3/x^3 lim x->0 (sin x-tan x)/sin (x^3) 烦人的数学微积分1、lim(x→0)Sin3x/Sin2x2、lim(x→0)x/3*Sin3x3、lim(x→0)[Xsin(3/x)+(tanx/2x)]4、lim(x→3)Sin(x-3)/(X^2-X-6)5、lim(x→∞)[1+(1/2x)^x6、lim(x→∞)(x+3/x)^x7、lim(x→0)（1-x/2)^1/x+118、求下列函数的间断 求极限 lim sin(x^2 * sin (1/x))/x x->0求极限 lim sin(x^2 * sin (1/x))/x x->0