设y=log(a)((x-3)/(x+3)) (a>0,a≠1)的定义域为[s,t),值域为(log(a)((at-a)),log(a)((as-a))].(1)求证s>3(2)求a的取值范围问是为了完成百度任务,我觉得这道题有一定难度,其实我已经做出来了,你的答案不
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![设y=log(a)((x-3)/(x+3)) (a>0,a≠1)的定义域为[s,t),值域为(log(a)((at-a)),log(a)((as-a))].(1)求证s>3(2)求a的取值范围问是为了完成百度任务,我觉得这道题有一定难度,其实我已经做出来了,你的答案不](/uploads/image/z/3872666-2-6.jpg?t=%E8%AE%BEy%3Dlog%28a%29%28%28x-3%29%2F%28x%2B3%29%29+%28a%EF%BC%9E0%2Ca%E2%89%A01%29%E7%9A%84%E5%AE%9A%E4%B9%89%E5%9F%9F%E4%B8%BA%5Bs%2Ct%EF%BC%89%2C%E5%80%BC%E5%9F%9F%E4%B8%BA%EF%BC%88log%28a%29%28%28at-a%29%29%2Clog%28a%29%28%28as-a%29%29%5D.%281%29%E6%B1%82%E8%AF%81s%EF%BC%9E3%282%29%E6%B1%82a%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%E9%97%AE%E6%98%AF%E4%B8%BA%E4%BA%86%E5%AE%8C%E6%88%90%E7%99%BE%E5%BA%A6%E4%BB%BB%E5%8A%A1%2C%E6%88%91%E8%A7%89%E5%BE%97%E8%BF%99%E9%81%93%E9%A2%98%E6%9C%89%E4%B8%80%E5%AE%9A%E9%9A%BE%E5%BA%A6%2C%E5%85%B6%E5%AE%9E%E6%88%91%E5%B7%B2%E7%BB%8F%E5%81%9A%E5%87%BA%E6%9D%A5%E4%BA%86%2C%E4%BD%A0%E7%9A%84%E7%AD%94%E6%A1%88%E4%B8%8D)
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