已知定义在R上的函数y=f(x),对任意x,y∈R,有f(x+y)=f(x)f(y),且当x>o时,f(x)>1已知定义在R上的函数y=f(x),对任意x,y∈R,有f(x+y)=f(x)f(y),且当x>o时,f(x)>11) 求证 对于x∈R,f(x)>0恒成立2)证 y=f(x)在R上为增函
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![已知定义在R上的函数y=f(x),对任意x,y∈R,有f(x+y)=f(x)f(y),且当x>o时,f(x)>1已知定义在R上的函数y=f(x),对任意x,y∈R,有f(x+y)=f(x)f(y),且当x>o时,f(x)>11) 求证 对于x∈R,f(x)>0恒成立2)证 y=f(x)在R上为增函](/uploads/image/z/3913254-54-4.jpg?t=%E5%B7%B2%E7%9F%A5%E5%AE%9A%E4%B9%89%E5%9C%A8R%E4%B8%8A%E7%9A%84%E5%87%BD%E6%95%B0y%3Df%28x%29%2C%E5%AF%B9%E4%BB%BB%E6%84%8Fx%2Cy%E2%88%88R%2C%E6%9C%89f%28x%2By%29%3Df%28x%29f%28y%29%2C%E4%B8%94%E5%BD%93x%3Eo%E6%97%B6%2Cf%28x%29%3E1%E5%B7%B2%E7%9F%A5%E5%AE%9A%E4%B9%89%E5%9C%A8R%E4%B8%8A%E7%9A%84%E5%87%BD%E6%95%B0y%3Df%28x%29%2C%E5%AF%B9%E4%BB%BB%E6%84%8Fx%2Cy%E2%88%88R%2C%E6%9C%89f%28x%2By%29%3Df%28x%29f%28y%29%2C%E4%B8%94%E5%BD%93x%3Eo%E6%97%B6%2Cf%28x%29%3E11%EF%BC%89+%E6%B1%82%E8%AF%81+%E5%AF%B9%E4%BA%8Ex%E2%88%88R%2Cf%28x%29%3E0%E6%81%92%E6%88%90%E7%AB%8B2%EF%BC%89%E8%AF%81+y%3Df%28x%29%E5%9C%A8R%E4%B8%8A%E4%B8%BA%E5%A2%9E%E5%87%BD)
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