作业帮化简（-11/6 π)+cos(12/5 π)tan（4π）-1/(cos(13π/3))
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化简（-11/6 π)+cos(12/5 π)tan（4π）-1/(cos(13π/3))
化简（-11/6 π)+cos(12/5 π)tan（4π）-1/(cos(13π/3))
化简（-11/6 π)+cos(12/5 π)tan（4π）-1/(cos(13π/3))
(-11/6 π)+cos(12/5 π)tan(4π) - 1/(cos(13π/3))
=-11π/6 - 1/cos(π/3)
=-11π/6 - 2
cos(α+5π/12)cos(α+π/6)+cos(π/12-α)cos(π/3-α) 化简
化简cos（π/12）*cos（5π/12）
化简（-11/6 π)+cos(12/5 π)tan（4π）-1/(cos(13π/3))
计算cos(a+5π/12)cos(a+π/6)+cos(π/12-a)cos(π/3-a）
求值:cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)
求值：cos(π/11)-cos(2π/11)+cos(3π/11)-cos(4π/11)+cos(5π/11)
cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)
化简sin（25π/12）cos（11π/6）-cos（11π/12）sin（5π/6）的值是
利用诱导公式求三角函数值 cos 6/65π一,利用诱导公式:cos（2kπ+α）=cosα （k∈Z）和cos（π－α）=－cosα 得出cos65π/6=cos(65π/6-10π)=cos(5π/6)=cos(π-π/6)=-cosπ/6=-√3/2二,又或者cos65π/6=cos(11π-1π/6)=-cos(
化简cos(π/12-α)-根号3cos(5π/12+α)
化简cos(π/6+x)+cos(π/6-x)
化简cos(π/6a)+cos(π／6-a)=
cos (π/12) × cos(5×π/12)的值
cos(π/12)cos(5π/12)=
化简cos^8(π/8)+cos^8(3π/8)+cos^8(5π/8)+cos^8(7π/8)
[sin(5π-α)cos(-π-α)]/[cos(α-π)cos(π/2+α)]化简
cos（π/11）cos（2π/11）cos（3π/11）cos（4π/11）cos（5π/11）怎么解
Cos[π/7] + Cos[2 π/7] + Cos[3 π/7] + Cos[4 π/7] + Cos[5 π/7] + Cos[6 π/7] + Cos[7π/7]过程思路 不要只有答案哦