lim(1/n+1/(n+1)^2+…+1/(2n)^2) n趋向于正无穷大
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lim(1/n+1/(n+1)^2+…+1/(2n)^2) n趋向于正无穷大
lim(1/n+1/(n+1)^2+…+1/(2n)^2) n趋向于正无穷大
lim(1/n+1/(n+1)^2+…+1/(2n)^2) n趋向于正无穷大
级数1 + 1/2^2 + 1/3^2 + …… + 1/n^2 + ……收敛(收敛到π^2/6)
所以上面极限就是0
如果是1/n + 1/(n+1) + …… + 1/(2n)的话,它是收敛到ln2的,因为
记f(n) = 1 + 1/2 + …… + 1/n
则极限 = lim [f(2n)-f(n)] = lim[ln2n + γ - lnn - γ] = ln2
其中γ是欧拉常数
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