若非零函数f(x)对任意实数x,y均有f(x+y)=f(x)×f(y)成立,且当x<0时,f(x)>1.(1)求证:f(x)>0.(2)求证:f(x)为减函数.(3)当f(4)=1/16时,解不等式f(x-3)×f(5)≤1/4.
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 23:00:48
![若非零函数f(x)对任意实数x,y均有f(x+y)=f(x)×f(y)成立,且当x<0时,f(x)>1.(1)求证:f(x)>0.(2)求证:f(x)为减函数.(3)当f(4)=1/16时,解不等式f(x-3)×f(5)≤1/4.](/uploads/image/z/3940468-52-8.jpg?t=%E8%8B%A5%E9%9D%9E%E9%9B%B6%E5%87%BD%E6%95%B0f%28x%29%E5%AF%B9%E4%BB%BB%E6%84%8F%E5%AE%9E%E6%95%B0x%2Cy%E5%9D%87%E6%9C%89f%28x%2By%29%3Df%28x%29%C3%97f%28y%29%E6%88%90%E7%AB%8B%2C%E4%B8%94%E5%BD%93x%EF%BC%9C0%E6%97%B6%2Cf%28x%29%EF%BC%9E1.%281%29%E6%B1%82%E8%AF%81%EF%BC%9Af%28x%29%EF%BC%9E0.%282%29%E6%B1%82%E8%AF%81%EF%BC%9Af%28x%29%E4%B8%BA%E5%87%8F%E5%87%BD%E6%95%B0.%283%29%E5%BD%93f%284%29%3D1%2F16%E6%97%B6%2C%E8%A7%A3%E4%B8%8D%E7%AD%89%E5%BC%8Ff%28x-3%29%C3%97f%285%29%E2%89%A41%2F4.)
xTn@z)#UUtܤ%
i()}M#hHU>i<~+SU ls9;6ҎQnͳ:ibȑho&/Z$VNȋCEutTB"ɂ&ti<*4Q.3C4E%;_
e4xw?GCM1d3o@Y%)o4
JU| H]sĂ<; QJ%v/Վq<%*`RAWV vQt^ECu*