等差数列中a5+a8=18,求a2+a3+a10+a11=?

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等差数列中a5+a8=18,求a2+a3+a10+a11=?
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等差数列中a5+a8=18,求a2+a3+a10+a11=?
等差数列中a5+a8=18,求a2+a3+a10+a11=?

等差数列中a5+a8=18,求a2+a3+a10+a11=?
a2+a3+a10+a11
=(a5-3d)+(a5-2d)+(a8+2d)+(a8+3d)
=2(a5+a8)
=2×18
=36

a3+a10=a5+a8=18
a2+a11=a5+a8=18
所以原式=18+18=36

a1+a12=a3+a10=a5+a8
则原式=36