张老师出示了问题:如图1,四边形ABCD是正方形,点E是边BC的中点.∠AEF=90°,且EF交正方形外角∠DCG的平分线CF于点F,求证:AE=EF.经过思考,小明展示了一种正确的解题思路:取AB的中点M,连接ME,
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![张老师出示了问题:如图1,四边形ABCD是正方形,点E是边BC的中点.∠AEF=90°,且EF交正方形外角∠DCG的平分线CF于点F,求证:AE=EF.经过思考,小明展示了一种正确的解题思路:取AB的中点M,连接ME,](/uploads/image/z/3963911-23-1.jpg?t=%E5%BC%A0%E8%80%81%E5%B8%88%E5%87%BA%E7%A4%BA%E4%BA%86%E9%97%AE%E9%A2%98%EF%BC%9A%E5%A6%82%E5%9B%BE1%2C%E5%9B%9B%E8%BE%B9%E5%BD%A2ABCD%E6%98%AF%E6%AD%A3%E6%96%B9%E5%BD%A2%2C%E7%82%B9E%E6%98%AF%E8%BE%B9BC%E7%9A%84%E4%B8%AD%E7%82%B9%EF%BC%8E%E2%88%A0AEF%3D90%C2%B0%2C%E4%B8%94EF%E4%BA%A4%E6%AD%A3%E6%96%B9%E5%BD%A2%E5%A4%96%E8%A7%92%E2%88%A0DCG%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BFCF%E4%BA%8E%E7%82%B9F%2C%E6%B1%82%E8%AF%81%EF%BC%9AAE%3DEF%EF%BC%8E%E7%BB%8F%E8%BF%87%E6%80%9D%E8%80%83%2C%E5%B0%8F%E6%98%8E%E5%B1%95%E7%A4%BA%E4%BA%86%E4%B8%80%E7%A7%8D%E6%AD%A3%E7%A1%AE%E7%9A%84%E8%A7%A3%E9%A2%98%E6%80%9D%E8%B7%AF%EF%BC%9A%E5%8F%96AB%E7%9A%84%E4%B8%AD%E7%82%B9M%2C%E8%BF%9E%E6%8E%A5ME%2C)
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