数列{an}中,a1=8,a4=2,且满足a(n+2)-2a(n+1)+an=0(n∈N+)(1)求{an}通项公式(2)设bn=1/(12-an)n,Sn=b1+b2+……bn,是否存在最大的整数m,使对任意n都有Sn>m/32总成立,若存在,求出m的值,若不存在在,说明理由.
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![数列{an}中,a1=8,a4=2,且满足a(n+2)-2a(n+1)+an=0(n∈N+)(1)求{an}通项公式(2)设bn=1/(12-an)n,Sn=b1+b2+……bn,是否存在最大的整数m,使对任意n都有Sn>m/32总成立,若存在,求出m的值,若不存在在,说明理由.](/uploads/image/z/3966386-50-6.jpg?t=%E6%95%B0%E5%88%97%7Ban%7D%E4%B8%AD%2Ca1%3D8%2Ca4%3D2%2C%E4%B8%94%E6%BB%A1%E8%B6%B3a%28n%2B2%29-2a%28n%2B1%29%2Ban%3D0%28n%E2%88%88N%2B%29%EF%BC%881%EF%BC%89%E6%B1%82%7Ban%7D%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F%EF%BC%882%EF%BC%89%E8%AE%BEbn%3D1%2F%2812-an%29n%2CSn%3Db1%2Bb2%2B%E2%80%A6%E2%80%A6bn%2C%E6%98%AF%E5%90%A6%E5%AD%98%E5%9C%A8%E6%9C%80%E5%A4%A7%E7%9A%84%E6%95%B4%E6%95%B0m%2C%E4%BD%BF%E5%AF%B9%E4%BB%BB%E6%84%8Fn%E9%83%BD%E6%9C%89Sn%EF%BC%9Em%2F32%E6%80%BB%E6%88%90%E7%AB%8B%2C%E8%8B%A5%E5%AD%98%E5%9C%A8%2C%E6%B1%82%E5%87%BAm%E7%9A%84%E5%80%BC%2C%E8%8B%A5%E4%B8%8D%E5%AD%98%E5%9C%A8%E5%9C%A8%2C%E8%AF%B4%E6%98%8E%E7%90%86%E7%94%B1.)
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