不好意思还有一个问题.求二重积分∫∫y*(根号下(1+x^2-y^2))dxdy,其中D是由直线y=x,x=-1,y=1所围成前面会解,最后答案中有个-1/3 ∫ (上标1,下表-1) [ (1+x^2-y^2)^(3/2) ] )(上标1,下标x) dx = -1/3
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![不好意思还有一个问题.求二重积分∫∫y*(根号下(1+x^2-y^2))dxdy,其中D是由直线y=x,x=-1,y=1所围成前面会解,最后答案中有个-1/3 ∫ (上标1,下表-1) [ (1+x^2-y^2)^(3/2) ] )(上标1,下标x) dx = -1/3](/uploads/image/z/3976937-17-7.jpg?t=%E4%B8%8D%E5%A5%BD%E6%84%8F%E6%80%9D%E8%BF%98%E6%9C%89%E4%B8%80%E4%B8%AA%E9%97%AE%E9%A2%98.%E6%B1%82%E4%BA%8C%E9%87%8D%E7%A7%AF%E5%88%86%E2%88%AB%E2%88%ABy%2A%EF%BC%88%E6%A0%B9%E5%8F%B7%E4%B8%8B%EF%BC%881%2Bx%5E2-y%5E2%EF%BC%89%EF%BC%89dxdy%2C%E5%85%B6%E4%B8%ADD%E6%98%AF%E7%94%B1%E7%9B%B4%E7%BA%BFy%3Dx%2Cx%3D-1%2Cy%3D1%E6%89%80%E5%9B%B4%E6%88%90%E5%89%8D%E9%9D%A2%E4%BC%9A%E8%A7%A3%2C%E6%9C%80%E5%90%8E%E7%AD%94%E6%A1%88%E4%B8%AD%E6%9C%89%E4%B8%AA-1%2F3+%E2%88%AB+%EF%BC%88%E4%B8%8A%E6%A0%871%2C%E4%B8%8B%E8%A1%A8-1%EF%BC%89+%5B+%281%2Bx%5E2-y%5E2%29%5E%283%2F2%29+%5D+%EF%BC%89%28%E4%B8%8A%E6%A0%871%2C%E4%B8%8B%E6%A0%87x%29+dx+%3D+-1%2F3)
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